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Relative Position

The system sh...

Question

The system shown in the figure is in equilibrium. The maximum value of $W$ . So that the maximum value of static frictional force on $100 k g$ body is $450 N$ , will be:-

A

100 N

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B

250 N

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C

450 N

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D

1000 N

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Solution

The correct option is C 450 N
System is in equilibrium
$T_{1} = W = T s i n 45 T_{2} = {(f_{s})}_{m a x} = T c o s 45 W = {(f_{s})}_{m a x} W = 450 N$

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