CameraIcon

SearchIcon

MyQuestionIcon

26

You visited us 26 times! Enjoying our articles? Unlock Full Access!

First Order Reaction

The t1/2 of...

Question

The $t_{1 / 2}$ of first order reaction is $60$ minutes. What percentage will be left after $240$ minutes?

Open in App

Solution

$k = \frac{2.303}{t} l o g \frac{A_{o}}{A_{t}}$
$t = \frac{2.303}{0.693 / 60} l o g \frac{A_{o}}{A_{t}}$
$240 = \frac{2.303}{0.693 / 60} l o g \frac{A_{o}}{A_{t}}$
$\frac{240 \times 0.639}{2.303 \times 60} = l o g \frac{A_{o}}{A_{t}}$
$l o g \frac{A_{o}}{A_{t}} = 1.2036$
Suppose $A_{o} = 100$
$A_{t} = 6.25$ .

Suggest Corrections

thumbs-up

1

Similar questions

Q. The half-life period of a

1^{s t}

order reaction is

60

minutes. What percentage will be left over after

240

t \frac{1}{2}

of first order reaction is 60 min. What will be

%

of substance left after 240 min?

Q. The half-life of a zero-order reaction is 30 minutes. What is the concentration of the reactant left after 60 minutes?

Q. The half-life period of a first-order reaction is 15 minutes. The amount of substance left after one hour will be:

Q. What fraction of a reactant showing first order remains after 40 minute if

t_{1 / 2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Integrated Rate Equations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

First Order Reaction

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon