The table below gives some known quantities for the pictured circuit. What is the current flowing through the resistor 3?
Battery Terminal Voltage 16.0 V
Voltmeter 1 Reading 8.0 V
Ammeter 1 Reading 13.0 A
Ammeter 2 Reading 7.0 A

8.0 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13.0 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.0 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16.0 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.0 A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E 6.0 A
Current flowing through resistor $R_{1}$ $I_{1} = 13.0$ A
This current splits up to flow through resistors $R_{2}$ and $R_{3}$ .
Current flowing through resistor $R_{2}$ $I_{2} = 7.0$ A
Thus current flowing through resistor $R_{3}$ $I_{3} = I_{1} - I_{2} = 13.0 - 7.0 = 6.0$ A

Suggest Corrections

Similar questions

2

3.0 V

20 A

5.0 V

{(1 + x)}^{10} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . + a_{10} x^{10}

{(a_{0} - a_{2} + a_{4} - a_{6} + a_{8} - a_{10})}^{2} + {(a_{1} - a_{3} + a_{5} - a_{7} + a_{9})}^{2}

Join BYJU'S Learning Program