The correct option is B 3.5
Volume Cumulativeof water(l) frequency1−262−3143−4264−5325−640
Here, N = 40.
⇒N2=20
∴ Median class is 3-4.
The formula for median of a grouped data is given by,
M = L + [n2 − cff]×h
where,
M = median of the grouped data
L = Lower limit of median class
n = Sum of frequencies
cf = Cumulative frequency of the class preceding the median class
f = frequency of the median class
and, h = class size
Substituting the given values, we get:
Median = 3 + 402 − 1412×1= 3 + 612= 3 + 12=3.5