Let the rate law be =k[OCl−]x[I−]y[OH−]z
From expt. (1), 1.75×10−4=k[0.0017]x[0.0017]y[1.0]z ...(i)
From expt. (2), 3.50×10−4=k[0.0034]x[0.0017]y[1.0]z ...(ii)
Dividing equation (ii) by equation (i),
3.50×10−41.75×10−4=[0.0034]x[0.0017]x
2=2x
x=1, i.e., first order with respect to OCl−
From expt. (1),
1.75×10−4=k[0.0017]x[0.0017]y[1.0]z ...(i)
From expt. (3),
3.50×10−4=k[0.0017]x[0.0034]y[1.0]z ...(iii)
Dividing equation (iii) by equation (i),
3.50×10−41.75×10−4=[0.0034]y[0.0017]y
or 2=2y
or y=1, i.e., first order with respect to I−
From expt. (1), 1.75×10−4=k[0.0017]x[0.0017]y[1.0]z ...(i)
From expt. (4),
3.50×10−4=k[0.0017]x[0.0017]y[0.5]z ...(iv)
Dividing equation (i) by equation (iv),
1.75×10−43.50×10−4=[1.0]z[0.5]z
or 12=2z
or 2−1=2z
z=−1, i.e., first order with respect to OH− is −1.
Rate law =k[OCl−][I−][OH−]
From expt. (1) k=1.75×10−4[OH−][OCl−][I−]=1.75×10−4×1.00.0017×0.0017
=60.55s−1