The table represents the prices for round-trip airplane tickets offered by Mumbai to New Delhi. Airlines C and E offer six non-stop flights each to New Delhi throughout the day at the prices shown in the table. Each airline flight can hold $170$ passengers. If all Airline C's flights are filled to its capacity and all Airline E's flights are filled to $90 %$ of its capacity, how much more revenue does Airline E generate than Airline C?

A B C D E F G H
Non-stop $N A$ $$ 340.20$ $$ 340.20$ $$ 536.20$ $$ 380.19$ $$ 382.20$ $$ 383.95$ $$ 429.00$
$1 +$ stops $$ 332.20$ $$ 376. 70$ $N A$ $$ 363.19$ $$ 395.59$ $$ 386.20$ $$ 392.45$ $$ 493.99$

$ 1 005.21

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$ 2 010.42

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$ 20 394.90

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$ 40 789.80

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Solution

The correct option is A $$ 2 010.42$
Airline E revenue $=$ cost per ticket $\times$ (No. of passengers) $\times$ (No. of trips)
No. of passengers of $E = \frac{90}{100} o f 170 = 153$
Cost $= 380.19$
Airline E revenue $= 380.18 \times 153 \times 6 =$ 349014.42$
Airline C revenue $= 340.20 \times 170 \times 6 =$ 347004$
Difference $=$ 2010.42$

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	A	B	C	D	E	F	G	H
Non-stop	$N A$	$$ 340.20$	$$ 340.20$	$$ 536.20$	$$ 380.19$	$$ 382.20$	$$ 383.95$	$$ 429.00$
$1 +$ stops	$$ 332.20$	$$ 376. 70$	$N A$	$$ 363.19$	$$ 395.59$	$$ 386.20$	$$ 392.45$	$$ 493.99$

The correct option is A $2010.42Airline E revenue = cost per ticket × (No. of passengers) × (No. of trips)No. of passengers of E=90100of170=153Cost =380.19Airline E revenue =380.18×153×6=349014.42$Airline C revenue =340.20×170×6=347004$Difference =2010.42$