  Question

# The table shows the Distribution of the Scores obtained by 155 shooters in a shooting competition. ScoresNo. of shooters0−101010−201220−301530−40840−502050−602460−70770−801180−903090−10018 Use a graph sheet to draw an ogive for the distribution. Using the graph estimate the Median.50 55 65 60

Solution

## The correct option is B 55 First , we prepare the Cumulative frequency table as follows : C.Ifcf0−10101010−20122220−30153730−4084540−50206550−60248960−7079670−801110780−903013790−10018155 Then draw the Graph of the 'less than ogive' and plot the points : (0,0) , (10,10) , (20,22) , (30,37) , (40,45) , (50,65) , (60,89) , (70,96) , (80,107) , (90,137) , (100,155)\ n = 155 which is odd Median will be given by - (n+12)th term. ∴ n+12 = 1562 = 78th term Take a point A on 78 on y - axis and from there draw a line parallel to the X - axis touching the ogive at point B.  From the point B, draw a vertical point which touches the x - axis at point C. The point C represents the required median which is 54. Median = 78th term = 55.  Suggest corrections   