Question

the tangent at a point C of a diameter AB when extended intersect at P. if $\angle PCA={110}^0$, find $\angle CBA$.

Answer 1

Given,

$\angle PCA=110$

$\angle ACB+\angle BCP=110$

$90+\angle BCP=110$

$\angle BCP=20$

$\angle BCP=\angle CAB=20$

$\angle CBA=90-20={70}^{\circ }$