The tangent at any point P on the parabola y2=4ax intersects the y−axis at Q. The tangent to the circum circle of triangle PQS(S is the focus) at Q is
A
a line parallel to x−axis
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B
y−axis
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C
a line parallel to y−axis
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D
None of these
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Solution
The correct option is Dy−axis Given equation of parabola is y2=4ax
Let P(at2,2at) be any point on the parabola. Equation of tangent at P is ty=x+at2 Since the tangent meets y−axis at Q i.e. x=0 ⇒y=at So, the coordinates of Q is (0,at). So, we draw the circumcircle of triangle PQS. So, from the graph , its clear that y−axis is the tangent to the circumcircle of triangle PQS at Q.