The tangent PT and the normal PN to the parabola y2=4ax at a point P on it meet its axis at points T and N, respectively. The locus of the centroid of the triangle PTN is a parabola, whose
A
vertex is (2a3,0)
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B
directrix is x = 0
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C
latus rectum is 2a3
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D
focus is (a, 0)
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Solution
The correct options are A vertex is (2a3,0) D focus is (a, 0) Equation of tangent and normal at point P(at2,2at) is ty=x+at2 and y=−tx+2at+at3 Let centroid of ΔPTN is R(h,k). ∴h=at2+(−at2)+2a+at23
and k=2at3⇒3h=2a+a(3k2a)2 ⇒3h=2a+9k24a ⇒9k2=4a(3h−2a) ∴ Locus of centroid is y2=4a3(x−2a3) ∴ Vertex (2a3,0); directrix x−2a3=−a3⇒x=a3 and latus rectum =4a3 ∴ Focus (a3+2a3,0),i.e.(a,0).