The tangent to the curve $y = x^{2} - 5 x + 5$ , parallel to the line $2 y = 4 x + 1$ , also passes through the point

⟮ \frac{1}{4}, \frac{7}{2} ⟯

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⟮ \frac{7}{2}, \frac{1}{4} ⟯

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⟮ - \frac{1}{8}, 7 ⟯

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⟮ \frac{1}{8}, - 7 ⟯

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Solution

The correct option is D $⟮ \frac{1}{8}, - 7 ⟯$

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Similar questions

y = x^{2} - 5 x + 5

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