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Question

The tangent to the curve y=x3+1 at (1, 2) makes an agnle θ with y axis, then the value of tan θ is.

A
3
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B
13
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C
13
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D
3
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Solution

The correct option is D 3
Given curve is y=x3+1
Differentiate it
dydx=3x2+0=3x2
Thus slope of tangent to the curve at the point (1,2) is
=dydxx=1=3(1)2=3
If line makes an angle θ with y-axis then it will make angle πθ with positive x-axis
Thus slope =tan(πθ)=3
tanθ=3

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