Question

The tangential acceleration of a body is $29.48m/s^2$ and its linear acceleration is $52.3m/s^2$. Find its radial acceleration. (in $m/s^2$)

• A. $43.1$
  
• B. $23.6$
  
• C. $56.31$
  
• D. $25.98$
  

Answer 1

The correct option is A $43.1$

The linear acceleration will be resultant of tangential acceleration and centripetal acceleration and angle between both is ${90}^o$.

So the radial acceleration is given by

$a_{radial}=\sqrt{a_{linear}^2-a_t^2}$

Given : $a_{linear}=52.3m/s^2$ and $a_t=29.48m/s^2$

$a_{radial}=\sqrt{(52.3{)}^2-(29.48{)}^2}=43.1m/s^2$