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Question

The tangential or shear stress on an oblique plane at an angle θ to the cross-section of a body which is subjected to a direct tensile stress (σ) is equal to

A
σ2 sin 2θ
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B
σ cos θ
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C
σcos2θ
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D
σsin2θ
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Solution

The correct option is A σ2 sin 2θ
We have σ=FA
For an oblique plane we have
FcosθA/cosθ=σ2sin2θ
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