Equation of Normal at a Point (x,y) in Terms of f'(x)
The tangents ...
Question
The tangents drawn from (2,3) to the ellipse 9x2+16y2=144 form a triangle with y-axis whose area is
A
5
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B
4
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C
2
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D
1
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Solution
The correct option is C 2 Equ of tangent is y – 3 = m(x – 2) ⇒y=mx+(3−2m)C2=a2m2+b2⇒m=0,−1 ∴ Equ of tangent are y = 3, x + y = 5 Vertices are(0,3), (2,3), (0,5)