wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The tangents to the curve y=sin(x+y),2πx2π that are parallel to the line x+2y=0 is

A
x+2yπ=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x+2y+π=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x2y+π=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2yπ=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A x+2yπ=0
B x+2y+π=0
Let (x1,y1) be the point of contact of one of the tangents.
Tangent is parallel to x+2y=0
Slope of the tangent is, m=12
y=sin(x+y)
dydx=12
cos(x+y)(1+dydx)=12
At (x1,y1), we get
cos(x1+y1)(112)=12
cos(x1+y1)=1x1+y1=π,π

So, y1=sin(x1+y1)=0
x1=π,π
Equations of tangents are
y0=12(xπ) and y0=12(x+π)

Hence, the required equation of the tangents are
x+2yπ=0 and x+2y+π=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Chords and Pair of Tangents
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon