wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The tangents to the curve y=(x2)21 at its points of intersection with the line xy=3, intersect at the point :

A
(52,1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(52,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(52,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(52,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (52,1)
xy3=0 (1)
will be chord of contact of the parabola
y=x24x+3
Let the required point is P(x1,y1), then chord of contact for point P is
y+y12=xx14(x+x1)2+3(2x14)xy+(4x1y1+6)=0 (2)

Comparing equation (1) and (2)
2x14=1, 4x1y1+6=3x1=52, y1=1
So, required point is (52,1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon