The tangents to the parabola $y^{2} = 4 x$ at the points $(1, 2)$ and $(4, 4)$ meet on the line

x = 3

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x + y = 4

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y = 3

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y = - 3

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Solution

The correct option is D $y = 3$
The point of intersection of two tangents from $t_{1}$ and $t_{2}$ is $(a t_{1} t_{2}, a (t_{1} + t_{2}))$
$t_{1} = 1, t_{2} = 2$
Hence Point of intersection is $(2, 3)$
Option C

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The tangents to the parabola y2=4x at the points (1,2) and (4,4) meet on the line

The correct option is D y=3The point of intersection of two tangents from t1 and t2 is (at1t2,a(t1+t2))t1=1,t2=2Hence Point of intersection is (2,3)Option C

The tangents to the parabola $y^{2} = 4 x$ at the points $(1, 2)$ and $(4, 4)$ meet on the line

The correct option is D $y = 3$
The point of intersection of two tangents from $t_{1}$ and $t_{2}$ is $(a t_{1} t_{2}, a (t_{1} + t_{2}))$
$t_{1} = 1, t_{2} = 2$
Hence Point of intersection is $(2, 3)$
Option C