The taxi fare in a city is as follows : For the first kilometre, the fare is Rs.8 and for the subsequent distance it is Rs.5 per kilometre. Taking the distance covered as x km and total fare as Rs.y, a linear equation for this information is _____.
A
5x+y+3=0
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B
5x−y+3=0
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C
5x+y−3=0
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D
5x−y−3=0
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Solution
The correct option is B5x−y+3=0 It is given that, If x=1⇒y=8rs.
Now, for the subsequent distance, it is Rs.5 per kilometer.
So, we can say If x=2⇒y=8+5(1)
Similarly, If x=3⇒y=8+5(2)
Now for the x distance, fare is y=8+5(x−1)⇒5x−y+3=0