Question

The taxi fare in a city is as follows: For the first kilometre, the fare is $Rs8$ and for the subsequence distance it is $Rs5perKm$. Taking the distance covered as $xKm$ and total fare as $Rsy.$ write linear equation for this information, and draw its graph.

Answer 1

x	0	1	2
y	3	8	13

Given, the total distance covered $=xkm=1+(x-1)km$

Fare For first kilometre $=8$

Fare for subsequent distance $=5perkm$

Fare for next $(x-1)km=5(x-1)$

Total fare $=y$

$8+5(x-1)=y$

$8+5x-5=y$

$5x-y+3=0$

Which is the required linear equation.

Or

$y=5x+3$

At $x=0$ ,then $y=3$, at $x=1,$ then $y=5+3=8$

At $x=2,$ then $y=10+3=13$ and so on.

Hence, this is the answer.