The taxi fare is Rs. 14 for the first kilometer and Rs. 2 for each additional kilometer. What will be the fair for 10 kilometers?
A
28
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B
32
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C
36
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D
40
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Solution
The correct option is B 32 Taxi fare for first kilometer =14 Taxi fare for two kilometers =14+2=16 Taxi fare for three kilometres =16+2=18 And so on.... This forms an AP with first term a=14 and common difference d=2 We know an=a+(n−1)d ⇒a10=14+(10−1)2 ⇒a10=14+18 ⇒a10=32 ⇒ taxi fare for first ten kilometres is Rs 32