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Question

The taxi fare is Rs. 14 for the first kilometer and Rs. 2 for each additional kilometer. What will be the fair for 10 kilometers?

A
28
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B
32
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C
36
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D
40
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Solution

The correct option is B 32
Taxi fare for first kilometer =14
Taxi fare for two kilometers =14+2=16
Taxi fare for three kilometres =16+2=18
And so on....
This forms an AP with first term a=14 and common difference d=2
We know
an=a+(n1)d
a10=14+(101)2
a10=14+18
a10=32
taxi fare for first ten kilometres is Rs 32

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