The temperature at Bar Harbor, Maine, was $- 3^{o}$ F. It then dropped during the night to
be $4$ times as cold. What was the temperature then?

12^{o}

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- 12^{o}

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16^{o}

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- 16^{o}

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Solution

The correct option is B $- 12^{o}$ F
Since the temperature is $4$ times as cold.
$∴$ Temperature then was $4 \times - 3 = - 12^{o}$ F

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The temperature at Bar Harbor, Maine, was −3o F. It then dropped during the night tobe 4 times as cold. What was the temperature then?

The correct option is B −12o FSince the temperature is 4 times as cold.∴ Temperature then was 4×−3=−12o F

The temperature at Bar Harbor, Maine, was $- 3^{o}$ F. It then dropped during the night to
be $4$ times as cold. What was the temperature then?

The correct option is B $- 12^{o}$ F
Since the temperature is $4$ times as cold.
$∴$ Temperature then was $4 \times - 3 = - 12^{o}$ F