Question

The temperature at noon was $\frac{91}{5}$ °F and at night it dropped by $\frac{20}{3}$ °F. Calculate the temperature at the night?

• A. $\frac{273}{15}$ °F
• B. $\frac{173}{5}$ °F
• C. $\frac{273}{5}$ °F
• D. $\frac{173}{15}$ °F

Answer 1

The correct option is D $\frac{173}{15}$ °F

Given:
The temperature at noon = $\frac{91}{5}$ °F
Temperature drop = $\frac{20}{3}$ °F
The temperature at night can be found by subtracting the drop in temperature from the temperature at day.

$\therefore$ The temperature at night = $\frac{91}{5}$ - $\frac{20}{3}$

= $\frac{273-100}{15}$

= ${\frac{173}{15}}^{\text{o}}$ F