The temperature at which the motion of particles theoretically ceases is

273

K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-273

K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

300 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0$ $K$
$V_{r m s} = \sqrt{\frac{γ R T}{M}}$
Theoretically speed ceases at $0 K$

Suggest Corrections

Similar questions

Calculate the approximate temperature of 27^∘C in Kelvin.

The temperature at which molecular motion ceases is ___ K.

^{\circ} C

O_{2}

300 K

N e

^{\circ} C

At what temperature (in centigrade) will the volume of a gas at $0^{0}$ C double itself while pressure remains constant?

Join BYJU'S Learning Program