Question

The temperature, at which the rms speed of gas molecules become double its value at 0${}^0$C , is

• A. 224${}^0$C
• B. 819${}^0$C
• C. 273${}^0$C
• D. 760${}^0$C

Answer 1

Answer: (B)

819${}^0$C

We know that $c^2\alpha T$
Where T is absolute temperature.
c doubles, so T becomes 4 times
so T' = 4T = 4 x 273K = 1092K = ${819}^{\circ }$C