Question

The temperature at which the root mean square velocity of the gas molecules would become twice of its value at $0^{o}C$ is :

• A. ${819}^{o}C$
• B. ${1092}^{o}C$
• C. ${1100}^{o}C$
• D. ${1400}^{o}C$

Answer 1

The correct option is A ${819}^{o}C$

$\frac{C_t}{C_0}=\sqrt{\frac{273+t}{273}}$

$C_t=2C_o$
$\Rightarrow$ $4\times 273-273$ = $t$
$\Rightarrow$ $t$ = ${819}^{0}C$