Question

The temperature at which the speed of sound in air becomes double of its value at $0$ is ________ .

Answer 1

Given , $T_1=0K=0+273=273K$ ,

$T_2=?$ ,

$v_1=v,v_2=2v$

We have , $v\propto \sqrt{T}$

Hence , $\frac{v_2}{v_1}=\sqrt{\frac{T_2}{T_1}}$

or $\frac{2v}{v}=\sqrt{\frac{T_2}{273}}$

or $T_2=4\times 273=1092K$