The temperature coefficient of a standard Cd-cell is -5-0 - 10-5 Vk-1 whose emf at 25 oC is 1-018 V- During the cell operation- the temperature will-

The correct option is A Increase ∵Δ H = Δ G + T Δ S = n FE_cell + nFT ( ∂ E/∂ T)_ρ [n = 2 for Cd ^2+ + 2e^ nbsp;→ Cd amp; putting other ...

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Standard XII

Chemistry

Nernst Equation

The temperatu...

Question

The temperature coefficient of a standard Cd-cell is $- 5.0 \times 10^{- 5} V k^{- 1}$ whose emf at 25 $^{o}$ C is 1.018 V. During the cell operation, the temperature will:

Increase

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Decreases

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Either

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Remains constant

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Solution

The correct option is A Increase
$∵ Δ H = Δ G + T Δ S$
$= - n F E_{c e l l} + n F T {(\frac{\partial E}{\partial T})}_{ρ}$ [n = 2 for Cd $^{2 +} + 2 e^{-} \to$ Cd & putting other values]
$= - 199.35 k J / m o l$
Now, $Δ H < O \Rightarrow$ Exothermic reaction
$\Rightarrow$ Heat will be released during cell reaction & increasing the temperature of system.

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The temperature coefficient of a standard Cd-cell is −5.0×10−5Vk−1 whose emf at 25oC is 1.018 V. During the cell operation, the temperature will:

The correct option is A Increase∵ΔH=ΔG+TΔS=−nFEcell+nFT(∂E∂T)ρ [n = 2 for Cd2++2e−→ Cd & putting other values]=−199.35kJ/molNow, ΔH<O⇒ Exothermic reaction ⇒ Heat will be released during cell reaction & increasing the temperature of system.

The temperature coefficient of a standard Cd-cell is $- 5.0 \times 10^{- 5} V k^{- 1}$ whose emf at 25 $^{o}$ C is 1.018 V. During the cell operation, the temperature will: