The temperature coefficient of emf of a cell designed as Zn|Zn2+(1M)||Cu2+(0.1M)|Cu is −1.4×10−4V per degree. Change in entropy for the reaction Zn+Cu2+0.1M⇌Zn2+1M+Cu at 27∘C is:(E∘cell=1.1V)
A
14 J
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B
27 J
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C
-14 J
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D
-27 J
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Solution
The correct option is D -27 J ΔS=nFdEcelldT|p=2×96500(−1.4×10−4)=−27.02J