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Question

The temperature coefficient of resistance of a wire is 0.00125 per °C. At 300 K, its resistance is 1 ohm. This resistance of the wire will be 2 ohm at
(IIT-JEE 1980)


A

1154°K

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B

1100°K

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C

1400°K

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D

1127°K

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Solution

The correct option is B

1100°K


Given,
At 300K,
R1=1Ω
R2 = 2Ω at some T
∝ = 0.00125 °C1
R=T
So R2=R1(1+T)
2 = 1( 1 + 0.00125 T)
T=10.00125
= 800
T2=T1+800
= 300 + 800
T2=1100K


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