The temperature coefficient of resistance of a wire is 0.00125 per °C. At 300 K, its resistance is 1 ohm. This resistance of the wire will be 2 ohm at (IIT-JEE 1980)
A
1154°K
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B
1100°K
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C
1400°K
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D
1127°K
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Solution
The correct option is B 1100°K Given, At 300K, R1=1Ω R2 = 2Ω at some T ∝ = 0.00125 °C−1 △R△=∝△T So R2=R1(1+∝△T) 2 = 1( 1 + 0.00125 △ T) △T=10.00125 = 800 ∴T2=T1+800 = 300 + 800 T2=1100K