Question

The temperature coefficient of resistance of a wire is $12.5\times {10}^{-4}/C^0$. At 300 K the resistance of a wire is 1 $\Omega$. At what temperature in K will the resistance of same wire will be 2 $\Omega$?

Answer 1

Formula used

$R_0=R_1(1+\propto △T)$

Final resistance $R_0$

$R_1$ = initial resistance

$2=1(1+12.5\times {10}^{-4}△T)1=(12.5\times {10}^{-4})△T△T=\frac{1}{12.5}\times {10}^{-4}△T=\frac{100000}{125}△T=800$

Final temperature =500K