wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The temperature coefficient of resistance of platinum is α=3.92×101 K1 at 20oC. Find the temperature at which the increase in the resistance of platinum wire is 10 of its value at 20oC

A
40.5oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
45.5oC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
48.5oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
43.5oC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 45.5oC

Given,

Resistance at 20oCis1Ω

Increase in temperature, ΔR=10Ω

ΔR=αR20ΔT=

10=3.92×101×1×(T20)

T=45.5oC

Hence, at 45.5oC resistance increased by 10Ω

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Dependence of Resistance on Temperature
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon