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Byju's Answer
Standard XII
Chemistry
Heat Capacity
The temperatu...
Question
The temperature of
1
mole of ideal gas increase from
18
o
to
55.1
o
as the gas is compressed adiabatically. Calculate
q
1
,
W
1
,
Δ
U
,
Δ
H
for this process assuming that
C
V
=
3
/
2
R
.
Open in App
Solution
n
=
1
m
o
l
e
;
T
1
=
291
K
;
T
2
=
328.1
K
Adiabatic process:
C
V
=
3
2
R
;
C
P
=
5
2
R
;
γ
=
5
3
W
=
n
R
Δ
T
γ
−
1
=
(
1
)
(
8.314
)
(
37.1
)
5
3
−
1
=
3
2
(
8.3
)
(
37.1
)
⇒
W
=
461.865
J
q
=
0
Δ
U
=
n
C
V
Δ
T
=
(
1
)
(
3
2
)
(
37.1
)
=
50.6
J
Δ
H
=
n
C
P
Δ
T
=
(
1
)
(
5
2
)
(
37.1
)
=
185.5
2
=
92.7
J
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