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Question

The temperature of 1 mole of ideal gas increase from 18o to 55.1o as the gas is compressed adiabatically. Calculate q1,W1,ΔU,ΔH for this process assuming that CV=3/2R.

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Solution

n=1 mole; T1=291K; T2=328.1K
Adiabatic process: CV=32R; CP=52R; γ=53

W=nRΔTγ1=(1)(8.314)(37.1)531=32(8.3)(37.1)
W=461.865 J

q=0
ΔU=nCVΔT=(1)(32)(37.1)=50.6 J
ΔH=nCPΔT=(1)(52)(37.1)=185.52=92.7 J

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