The temperature of $5 m o l$ of a gas which was held at constant volume was changed from $100^{o} C t o 120^{o} C$ . The change in internal energy was found to be $80 J$ . The total heat capacity of the gas at constant volume will be equal to

8 J K^{- 1}

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0.8 J K^{- 1}

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4 J K^{- 1}

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0.4 J K^{- 1}

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Solution

The correct option is C $4 J K^{- 1}$
Heat capacity is energy given to change the temperature of a substance by $1^{o} C$
Therefore, $\frac{80}{20} = 4 J / K$
option(C)

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The temperature of 5 mol of a gas which was held at constant volume was changed from 100oC to 120oC. The change in internal energy was found to be 80 J. The total heat capacity of the gas at constant volume will be equal to

The correct option is C 4 JK−1Heat capacity is energy given to change the temperature of a substance by 1oCTherefore,8020=4 J/Koption(C)

The temperature of $5 m o l$ of a gas which was held at constant volume was changed from $100^{o} C t o 120^{o} C$ . The change in internal energy was found to be $80 J$ . The total heat capacity of the gas at constant volume will be equal to

The correct option is C $4 J K^{- 1}$
Heat capacity is energy given to change the temperature of a substance by $1^{o} C$
Therefore, $\frac{80}{20} = 4 J / K$
option(C)