The temperature of 5 mol of a gas which was held at constant volume was changed from 100- C to 120- C- The change in internal energy was found to be 80 J- The total heat capacity of the gas at constant volume will be equal to

The correct option is B 4 J/K Δ U=C_VΔ P C_V=Δ UΔ T=80J20K=4J/K ...

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Standard XII

Chemistry

First Law of Thermodynamics

The temperatu...

Question

The temperature of $5 m o l$ of a gas which was held at constant volume was changed from $100^{\circ} C$ to $120^{\circ} C$ . The change in internal energy was found to be $80 J$ . The total heat capacity of the gas at constant volume will be equal to

8 J / K

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0.8 J / K

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4 J / K

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0.4 J / K

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Solution

The correct option is B $4 J / K$
$Δ U = C_{V} Δ P$
$⟹ C_{V} = \frac{Δ U}{Δ T} = \frac{80 J}{20 K} = 4 J / K$

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The temperature of 5mol of a gas which was held at constant volume was changed from 100∘C to 120∘C. The change in internal energy was found to be 80J. The total heat capacity of the gas at constant volume will be equal to

The correct option is B 4J/KΔU=CVΔP⟹CV=ΔUΔT=80J20K=4J/K

The temperature of $5 m o l$ of a gas which was held at constant volume was changed from $100^{\circ} C$ to $120^{\circ} C$ . The change in internal energy was found to be $80 J$ . The total heat capacity of the gas at constant volume will be equal to

The correct option is B $4 J / K$
$Δ U = C_{V} Δ P$
$⟹ C_{V} = \frac{Δ U}{Δ T} = \frac{80 J}{20 K} = 4 J / K$