The temperature of 5moles of a gas which was held at constant volume was changed from 100oC to 120oC. The change in the internal energy of the gas was found to be 80J, the total heat capacity of the gas at constant volume will be equal to
A
8J/K
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B
0.8J/K
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C
4.0J/K
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D
0.4J/K
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Solution
The correct option is C4.0J/K dU=nCvdT or, 80=5×Cv(120−100) Cv=4.0J/K