Question

The temperature of a body is 3000K. The wavelength corresponding to maximum emission of radiation will be

• A. $1M$
• B. $1\dot{A}$
• C. $9.76\times {10}^{-7}$ m
• D. $48.8\times {10}^{-7}$ m

Answer 1

Answer: (C)

$9.76\times {10}^{-7}$ m

Wien's displacement law states that the black body radiation for different temperatures peaks at a wavelength inversely proportional to the temperature.
In other words ${\lambda }_m\times T=b$
where ${\lambda }_m$ is maximum wavelength of the radiation, $T$ is the temperature and $b$ is Wien's displacement constant equal to $2.9\times {10}^{-3}m/K$
${\lambda }_m=\frac{b}{T}=\frac{2.9\times {10}^{-3}}{3000}=9.67\times {10}^{-7}m$
option (C) is the correct answer.