The temperature of a furnace is 2324oC and the intensity is maximum in its radiation spectrum nearly at 1200˚A. If the intensity of spectrum in a star is maximum nearly at 4800˚A. Find the surface temperature of the star.
A
6219.50C
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B
649.25 K
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C
2597 K
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D
25970C
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Solution
The correct option is B 649.25 K By Wien's displacement Law: λmT=constant ∴λm1T1=λm2T2 ∴T2=λm1λm2T1=12004800×(2324+273) since T is in absolute scale ∴T2=14×2597=649.25K