The temperature of a room heated by a heater is 20∘C when outside temperature is −20∘C and it is 10∘C when the outside temperature is −40∘C. The temperature of the heater is
A
80∘C
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B
100∘C
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C
40∘C
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D
60∘C
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Solution
The correct option is B60∘C Let the temperature of the heater be, ToC Now, if the above conditions satisfy, then, T−20−20−20=T−10−40−10 Solving the above equation for T, gives us T=60oC