The temperature of a substance increases by 27- C- On the Kelvin scale this increase is equal to

The correct option is C 27 K Suppose, C= temperature at Celsius scaleK= nbsp;temperature at Kelvin scaleNow, K=C+273^∘ But the change in the temper ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Physics

Inter-Conversion of Temperature in Different Scales

The temperatu...

Question

The temperature of a substance increases by $27^{\circ} C$ . On the Kelvin scale this increase is equal to

300 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.46 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $27 K$
Suppose, C= temperature at Celsius scale
K= temperature at Kelvin scale
Now,
$K = C + 273^{\circ}$
But the change in the temperature will be same by cancelling the $273^{\circ}$ factor.
So, $Δ^{\circ} C = Δ^{\circ} K$

Suggest Corrections

Similar questions

Q. The temperature of a gas increased by

10^{o} C

. The equivalent increase on the Kelvin scale is

Q. A temperature difference of

27^{\circ} C

on the Kelvin scale is equal to a difference of :

Q. The temperature of an iron piece is increased from

30^{\circ} C

90^{\circ} C

. Find the change in its temperature on the Fahrenheit scale and on the Kelvin scale.

Q. On the centigrade scale, the temperature of a body increases by

30

degrees. The increase in temperature on the Fahrenheit scale is :

Q. By what factor does the rate of a reaction increase when
a. Temperature increase from

300 K

360 K

(temperature coefficient of reaction is

2

).
b. Temperature increase from

300 K

325 K

(temperature coefficient of reaction is

3

Join BYJU'S Learning Program

The temperature of a substance increases by 27∘C. On the Kelvin scale this increase is equal to

The correct option is C 27KSuppose, C= temperature at Celsius scaleK= temperature at Kelvin scaleNow,K=C+273∘But the change in the temperature will be same by cancelling the 273∘ factor. So, Δ∘C=Δ∘K

The temperature of a substance increases by $27^{\circ} C$ . On the Kelvin scale this increase is equal to

The correct option is C $27 K$
Suppose, C= temperature at Celsius scale
K= temperature at Kelvin scale
Now,
$K = C + 273^{\circ}$
But the change in the temperature will be same by cancelling the $273^{\circ}$ factor.
So, $Δ^{\circ} C = Δ^{\circ} K$