The temperature of a wire of length 1 m and area of cross section1 cm2 is increased from 0- C to 100- C- If the length of rod is not allowed to increase- then force developed will be - 10-5 -C and Y - 1011 N-m2

F (force developed) =Y∝ θ =10^11×10^ 4×10^ 5× 100=10^4N ...

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Thermal Stress

The temperatu...

Question

The temperature of a wire of length 1 m and area of cross section
$1 c m^{2}$ is increased from $0^{\circ} C$ to $100^{\circ} C$ . If the length of rod is not allowed to increase, then force developed will be $(α = 10^{- 5} / C a n d Y = 10^{11} \frac{N}{m^{2}})$

10^{3}

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10^{4}

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10^{5}

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10^{9}

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1

c m^{2}

0^{\circ} C

100^{\circ} C

,

(α = 10^{- 5} /^{\circ} C

Y = 10^{11} N / M^{2})

1 c m^{2}

0^{\circ} C

100^{\circ} C

(α = 10^{- 5} / C a n d Y = 10^{11} \frac{N}{m^{2}})

2 m

1 {c m}^{2}

0^{\circ} C

80^{\circ} C

Y = 10^{10} N / m^{2}, α = 10^{- 6} /^{o} C

2 m

1 {cm}^{2}

0^{\circ} C

80^{\circ} C

Y = 10^{10} {N/m}^{2}, α = 10^{- 6} /^{\circ} C

2 m

1 {cm}^{2}

0^{\circ} C

80^{\circ} C

Y = 10^{10} {N/m}^{2}, α = 10^{- 6}^{\circ} C

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