The temperature of an ideal gas is increased from $120 K$ to $480 K$ . If at $120 K$ , the root mean square speed of the gas molecules is v then at $480 K$ it will be

Q. The temperature of an ideal gas is increased from

120 K

480 K

. If at

120 K

, the root mean square speed of gas molecules is v, then at

80 k

, it will be

Q. the temperature of an ideal gas is increased from

120 K

480 K

. If at

120 K

.If at

120 K

, the root mean square speed of the gas molecules is

^{'} v^{'}

,then

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The temperature of an ideal gas is increased from 120K to 480K. If at 120K, the rms velocity of the gas molecules is vrms, then at 480K, it becomes.

The correct option is B 2vrmsvrms2vrms1=√T2T1=√480120=2vrms2=2(vrms)

The temperature of an ideal gas is increased from $120$ K to $480$ K. If at $120$ K, the rms velocity of the gas molecules is $v_{r m s}$ , then at $480$ K, it becomes.

The correct option is B $2 v_{r m s}$
$\frac{v_{r m s_{2}}}{v_{r m s_{1}}} = \sqrt{\frac{T_{2}}{T_{1}}} = \sqrt{\frac{480}{120}} = 2$

$v_{r m s_{2}} = 2 (v_{r m s})$