The temperature of an ideal gas is increased from 140 K to 560 K. If at 140 K the Root Mean Square velocity of the gas molecules is u, at 560 K it becomes:
A
5u
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B
2u
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C
u/2
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D
u/4
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Solution
The correct option is B 2u The root mean square velocity is directly proportional to the square root of temperature. Thus when the temperature increases from 140 K to 560 K, the root mean square velocity increases from u to √560140u=2u.