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Byju's Answer
Standard XII
Physics
Reynold's Number
The temperatu...
Question
The temperature of an spherical isolated black body falls from
T
1
to
T
2
in time
t
. Then time
t
is
A
t
∝
(
1
T
2
−
1
T
1
)
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B
t
∝
(
1
T
2
2
−
1
T
2
1
)
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C
t
∝
(
1
T
3
2
−
1
T
3
1
)
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D
t
∝
(
1
T
4
2
−
1
T
4
1
)
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Solution
The correct option is
C
t
∝
(
1
T
3
2
−
1
T
3
1
)
Power radiated
P
=
4
π
r
2
σ
T
4
=
−
(
m
s
d
T
d
t
)
−
d
T
T
4
=
4
π
r
2
σ
d
t
m
s
=
c
d
t
−
∫
T
2
T
1
d
T
T
4
=
c
t
⇒
t
=
K
[
1
T
3
2
−
1
T
3
1
]
Suggest Corrections
3
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− T
1
(b)
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2
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2
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3
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