The temperature of first object is 36-C and that of second object is 36-F- Which is hotter than the other-

The correct option is A First object T _ 1 =36 #8451;, T _ 2 =36 #8457; #160;Now, charge T _ 1 in to #8457;. F _ 1 = 9 5 × C+32 ...

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Standard XII

Physics

The 'e' Equation

The temperatu...

Question

The temperature of first object is $36^{\circ} C$ and that of second object is $36^{\circ} F$ . Which is hotter than the other?

First object

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Second object

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Both have same hotness

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Cannot be determined

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Solution

The correct option is A First object
$T_{1} = 36 ℃, T_{2} = 36 ℉$
Now, charge $T_{1}$ in to $℉ . F_{1} = \frac{9}{5} \times C + 32 = \frac{9}{5} \times 36 + 32 = 64.8 + 32 = 96.8 ℉ T_{1} = 96.8 ℉ & T_{2} = 36 ℉$
Hence, first object is hotter than the other.

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The temperature of first object is 36∘C and that of second object is 36∘F. Which is hotter than the other?

The correct option is A First objectT1=36℃,T2=36℉ Now, charge T1 in to ℉.F1=95×C+32=95×36+32=64.8+32=96.8℉T1=96.8℉&T2=36℉ Hence, first object is hotter than the other.

The temperature of first object is $36^{\circ} C$ and that of second object is $36^{\circ} F$ . Which is hotter than the other?

The correct option is A First object
$T_{1} = 36 ℃, T_{2} = 36 ℉$
Now, charge $T_{1}$ in to $℉ . F_{1} = \frac{9}{5} \times C + 32 = \frac{9}{5} \times 36 + 32 = 64.8 + 32 = 96.8 ℉ T_{1} = 96.8 ℉ & T_{2} = 36 ℉$
Hence, first object is hotter than the other.