The temperature of gas is raised from $27^{o}$ C to $927^{o}$ C. The rms speed is?

\sqrt{\frac{927}{27}}

times the earlier value

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Remain the same

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Gets halved

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Get doubled

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\sqrt{\frac{927}{27}}$ times the earlier value
We know $V_{r m s} = \sqrt{\frac{3 R T}{M}}$
$\frac{V_{r m s} a t h i g h e r t e m p e r a t u r e}{V_{r m s} a t l o w e r t e m p e r a t u r e} = \sqrt{\frac{\frac{3 R (927)}{M}}{\frac{3 R (27)}{M}}} = \sqrt{\frac{927}{27}}$

Suggest Corrections

Similar questions

The temperature of the gas is raised from 27 $^{\circ}$ C to 927 $^{\circ}$ C, the root mean square velocity is

27^{\circ} C

927^{\circ} C

27^{\circ} C

927^{\circ} C

27^{\circ} C

927^{\circ} C

27^{o} C

927^{o} C

Join BYJU'S Learning Program