The temperature of hot and cold ends of a 20cm long rod in thermal steady state are at 100oC and 20oC respectively. The temperature at the centre of the rod is
A
30oC
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B
40oC
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C
50oC
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D
60oC
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Solution
The correct option is C60oC Temperature gradient=100−2020=4∘C/cm Temperature at centre =100−(4×10)=60∘C