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Question

The temperature of hot junction of a thermo-couple changes from 80C to 100C.The percentage change in thermo-electric power is


A
80%
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B
10%
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C
20%
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D
25%
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Solution

The correct option is D 80%

We know the thermoelectric power (for thermocouple) is given by

P=dEdT=πT

when, the temperature of hot junction of a thermocouple changes from 80C to 100C

Then p1=π80 and P2=π100
The change in thermoelectric power is δ=P1P2

Now, the percentage change in thermoelectric power is

δP×100P=P1P2P1
δP×100P=20



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