Question

The temperature of n moles of an ideal gas is increased from T to 4T through a process for which pressure where a is constant. The work done by gas is:

• A. nRT
• B. 4nRT
• C. 2nRT
• D. 6nRT

Answer 1

The correct option is D

6nRT

PV =nRT
$V=\frac{nRT}{P}V=\frac{nRT}{a}T=\frac{nR{T}^2}{a}\therefore P=\frac{a}{T}dV=\frac{2nRT}{a}dtdW={\int }_T^{4T}PdV={\int }_T^{4T}P.\frac{2nRT}{a}dt={\int }_T^{4T}\frac{a}{T}.\frac{2nRT}{a}dtW=6nRT$